DataWeave Xml input to Java object

DataWeave Xml input to Java object

This tutorial explains how to develop a DataWeave transformation input xml to Java Object.

Pre-requisite:

1. Anypoint Studio 5.2.0
2. Mule ESB Runtime 3.7.1
3. xml input files.

Input XML File

<user> <name>Annie</name> <lastName>Point</lastName> </user>

Mule Flow

Mule Source

<http:listener-config name="HTTP_Listener_Configuration" host="0.0.0.0" port="8081" doc:name="HTTP Listener Configuration"/> <flow name="testweaveFlow"> <http:listener config-ref="HTTP_Listener_Configuration" path="/" metadata:id="cab0526f-779e-427c-9a33-be44f9b12696" doc:name="HTTP"/> <dw:transform-message doc:name="Transform Message"> <dw:input-payload doc:sample="json.json"/> <dw:set-payload><![CDATA[%dw 1.0 %type user = :object { class: "testweave.User" } %output application/java --- { firstName: payload.user.name, lastName: payload.user.lastName } as :user]]></dw:set-payload> </dw:transform-message> <byte-array-to-string-transformer doc:name="Byte Array to String"/> </flow>

In the transform code I created the Object type in the header

“ %type user = :object { class: "testweave.User"} ”

And the payload of the transform is converted to User Object using the transform logic as below.

{

firstName: payload.user.name,

lastName: payload.user.lastName

} as :user

 DataWeave

User.java

package testweave; public class User { private String firstName; private String lastName; public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } @Override public String toString() { // TODO Auto-generated method stub return this.firstName+" "+this.lastName; } }